xmlns:fo breaks xsl cust layer

[Sean Wheller <sean@enbaya.co.za>]

Hi,

Found this hack and decided it was a good idea for my current purpose.
http://sources.redhat.com/ml/docbook-apps/2003-q2/msg00849.html

But when I add the xmlns:fo to the xsl:stylesheet I get:
F javax.xml.transform.TransformerException: ElemTemplateElement error: 
inline.boldmonoseq

The offending parts are as follows:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; 
xmlns:fo="http://www.w3.org/1999/XSL/Format"; version="1.0">

<!-- Inline Formatting -->
    <xsl:template match="filename">
      <xsl:call-template name="inline.boldmonoseq"/>
    </xsl:template>
    <xsl:template match="application">
      <xsl:call-template name="inline.boldseq"/>
    </xsl:template>
    <xsl:template match="guibutton">
      <xsl:call-template name="inline.boldseq"/>
    </xsl:template>
    <xsl:template match="guilabel">
      <xsl:call-template name="inline.italicseq"/>
    </xsl:template>
    
    <!-- Page Break use &lt?pagebreak?;&gt; to insert a page break -->
    <xsl:template match="processing-instruction('pagebreak')">
        <fo:block break-after="page"/>
    </xsl:template>

When I comment the whole of the Inline Formatting templates the xsl is valid.

Any ideas?
 
---------------------------------------------------------------------------------------------------
Sean Wheller