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Subject: Re: suppressing everything but the content of <body> in xhtml output
OK, found another tip from
http://www.dpawson.co.uk/docbook/styling/custom.html:
<xsl:template match="*" mode="process.root">
<xsl:call-template name="root.messages"/>
<xsl:apply-templates select="."/>
</xsl:template>
This gives me a root node of <div class="article"> in the output, BUT I
still get this before it:
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE div PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd";>
How can I supress that as well? This content is going into an existing
site built with PHP.
Thanks.
On 6/12/2007 3:05 PM, Brett Leber wrote:
> Hello,
>
> I'd like to output only the content of the xhtml document's <body> (ie,
> no <html>, <head>, or <body> tags). I found an old post that seemed to
> be what I needed, but the XSL customization didn't work for me (granted,
> it's 5 years old):
>
> Subject: Re: DOCBOOK-APPS: Removing <html>,<head> & <body>
> * From: Gisbert Amm <gia@webde-ag.de>
> * To: Fredrik Svensson <fred@ludd.luth.se>
> * Date: Wed, 04 Sep 2002 10:21:26 +0200
>
> > Currently the HTML head stuff is output by
> > this template in html/docbook.xsl:
> >
> > <xsl:template match="*" mode="process.root">
> >
> > If you only want to modify this for articles,
> > you could add a template in mode "process.root"
> > to your html customization layer:
>
> > <xsl:template match="article" mode="process.root">
> > <xsl:apply-templates select="."/>
> > </xsl:template>
>
> > Then it will not output the <head><body> stuff, but
> > it will process everything in the document
> > as html.
>
> I'm using the DocBook 5 stylesheets, and xhtml/docbook.xsl. Any hints?
>
> thanks,
>
> Brett
>
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