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Subject: RE: [docbook-apps] Custom numbering scheme for a DocBook document(legal style stylesheet)
> I assumed that dblatex creates labels using the code in labels.xsl. But this
> is wrong; the numbering of headings is controlled by the settings that apply
> to \chapter, \section, \subsection etc. in the generated LaTeX file.
>
> I suppose that it is possible to customize the LaTeX numbering scheme to
> achieve what you want, but I cannot say much more than that.
>
> Mauritz
I have made the following question in DocBook and XSL forums [1][2], but
they have told me that I have to ask it here, because I use dblatex
0.2.12-4 and so, the problem is that the document is converted to latex,
and then to PDF. Therefore, some changes in XSL are ignored
(specifically, those described in [2])
Any ideas? I explain myself below, and I attach an example.
So: I have to change the latex stylesheet necessarily to achieve the
expected result, described below.
[1]
http://lists.oasis-open.org/archives/docbook-apps/201010/msg00060.html
[2]
http://www.biglist.com/lists/lists.mulberrytech.com/xsl-list/archives/201010/msg00203.html
--------- Mensaje reenviado --------
De: Néstor Amigo Cairo <nestor@aberi.org>
Para: xsl-list@lists.mulberrytech.com
Asunto: Customizing DocBook numbering scheme using XSL (legal style)
Fecha: Thu, 14 Oct 2010 10:57:39 +0200
Hello,
I'm using dblatex v. 0.2.12-4 (GNU/Linux Ubuntu Lucid 10.04 64bit).
===
I'm trying to number DocBook document in the 'legal' (lawyer) style, to
say:
1 Chapter one
Article 1. Article one
Article 2. Article two
2 Chapter two
Article 3. Article three (*not* 'one' again)
Article 4. Article four (*not* 'two' again)
=
**I would just like to change <xsl:number> element to have the attribute
"level=any" on the title of a <section> element.**
===
I have used code from
http://www.dpawson.co.uk/xsl/sect2/N5758.html#d7876e154 (recommended
here, but simplified)
===
<xsl:template match="sect1">
<xsl:number level="any" from="chapter" format="1. "/>
<xsl:apply-templates/>
</xsl:template>
===
I have carefully read the documentation, and I understand how XSL works.
I have tried many different solutions, from different sites, but I have
got no positive results.
I have read on the book that XSL works with parameters, so I have tried
also the following (no positive result):
<xsl:param name="section.number.level">any</xsl:param>
and
<xsl:param name="section.title.number.level">any</xsl:param>
But I am stuck because I cannot change the element <xsl:number> without
having to rewrite a new template from scratch.
Any ideas? Thanks.
--
Néstor Amigo -- www.aberi.org -- +34 687 967 481 (lu-vi, 9-13h)
Presidente de la Asociación por la Libertad de la Información
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