Your example is confusing, because in standard DocBook,
<row> does not have "entry" attributes, only <entry> child
elements.
But assuming you know that and this is really what you
want, it sounds like you are saying that you want to use the concatenated values
of the other attributes as the link ID. I think that you would do that not by
dynamically adding a "linkend" attribute, but by modifying the "xref" template
so that it retrieves the values of those other attributes
directly; something like this:
<xsl:variable name="linkID" select="@linkend"
/>
<xsl:choose>
<xsl:when test="id( $linkID
)">
<xsl:call-template name="createURI">
<xsl:with-param name="element" select="id( $linkID )"
/>
</xsl:call-template>
</xsl:when>
<xsl:otherwise>
<xsl:call-template name="createURI">
<xsl:with-param name="element" select="*[concat(@entry1, @entry2, @entry3) =
$linkID]" />
</xsl:call-template>
</xsl:otherwise>
</xsl:choose>
You would have to make the entry text
retrieval match the exact pattern you want, but that's generally how I'd
approach it.
From: Nancy Brandt
[mailto:]
Sent: Tuesday, October 20, 2009 5:30
AM
To:
Cc:
Subject: A tricky xref
problem
Hi all,
I wonder if there is a way to extract a
text string and pass it as a value for the <xref linkend=""/>
expression. For example, when I write:
Some text
text text (see ref=[sect_test]),
I would like
to take the text within the [ ] delimiters and pass it as a value for
the linkend attribute of the xref element called in my customized table
template. The reason for this special workaround is that I've
created a custom template that enables you to add a table row with its
entries using one command, like
so:
<table>
...
<row entry1="red" entry2="blue"
entry3="black"/> -which saves a lot of typing.
So, if I wish
to add a reference to some section from within entry1, I can't
write:
<row entry1="red (refer to <xref
linkend="sect_test"/>)" entry2="blue" entry3="black"/>
I
need somehow to customize my table template that says something
like:
...
<xsl:for-each select="row">
<row>
<xsl:if
test="$entry1">
<entry>
<xsl:value-of
select="@entry1"/>
<xsl:if
test="contains('xref')">
<xref>
<xsl:copy-of
select="@*"/>
<xsl:attribute
name="linkend">
<xsl:copy-of
select="@*"/>
<xsl:value-of
select="<extracted_text_string>"/>
</xsl:attribute>
</xref>
</xsl:if>
</entry>
</xsl:if>
...
</row>
</xsl:for-each>
...
Please,
advise me how to extract the text string from within [ ] delimiters to
pass it as a value for the <xref> expression.
Thanks a lot
in advance!!!
Best
wishes,
Nancy
