Hi Frank,
For what use case does the user need to know if the type is a data type
wrapper?
-Blaise
Frank Budinsky wrote:
> Unless somebody can think of a better approach, I'd like to suggest that
> we also vote on this in next weeks call.
>
> Thanks,
> Frank
>
> ----- Forwarded by Frank Budinsky/Toronto/IBM on 08/20/2008 03:15 PM -----
>
> Frank Budinsky/Toronto/IBM
> 08/18/2008 05:19 PM
>
> To
>
> cc
>
> Subject
> [sdo] Issue 118 - Creating wrapper objects for simple types
>
>
>
>
>
> If I'm not mistaken, SDO 118 has already been resolved in JSR235. We've
> agreed that DataFactory.create(someSimpleType) must return a wrapper.
>
> What's still missing, is a way for clients to know if a type is a wrapper.
>
> Proposal: Type.isDataTypeWrapper(). This would return true for any type
> that has the special "value" property (including formally defined types in
> an XSD).
>
> Please let me know if you have any comments or better alternatives?
>
> Thanks,
> Frank.
>
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