There are some basic flaws in your logic.
The XML fragment:
<nodexhtml>
<html><h1>Hello</h1></html>
</nodexhtml>
cannot appear at this place in the stylesheet. This violates the XSLT
(1.0 & 2.0) syntax.
Alternate is to wrap this fragment in a variable (as follows):
<xsl:variable name="rtf">
<nodexhtml>
<html><h1>Hello</h1></html>
</nodexhtml>
</xsl:variable>
Then you can output this fragment from elsewhere in the stylesheet as:
1)
<xsl:copy-of select="$rtf/nodexhtml/*" /> (in XSLT 2.0)
or as:
2)
<xsl:copy-of select="xx:node-set($rtf)/nodexhtml/*" /> (in XSLT 1.0)
In both cases 1) and 2), the XML fragment is parsed.
PS: There is a list, http://www.mulberrytech.com/xsl/xsl-list
dedicated to XSLT topics.
On 11/24/07, http://www.pas-world.com <> wrote:
> Hello,
> How I can output from XSLT unparsed xml?
>
>
> <xsl:stylesheet>
> <xsl:template match="">
>
> <xsl:value>
> <!-- Here I need the unparsed code -->
> <xsl:value-of select="nodetexhtml">
> </xsl:template>
>
> <nodexhtml>
> <html><h1>Hello</h1></html>
> </nodexhtml>
>
> </xsl:stylesheet>
>
>
> Output of apply XSLT should be the unparsed content of nodexhtml, should
> be unparsed xhtml:
>
> <html><h1>Hello</h1></html>
>
>
> I'm trying with Xinclude but do not work. Any suggestion is welcome.
> Thanks in advance.
--
Regards,
Mukul Gandhi
